The route-policy defined by a router is as shown in the figure. [HUAWEI]ip ip-prefix 1 permit 11.1.0.0 16 [HUAWEI]route-policy test-set cost permit node 10 [HUAWEI]route-policy if-match ip-prefix 1…

Question

Options

• ARoute 11.1.0.0/16 will continue to match node 20 after passing node 10, and the final cost is set to
• BThe cost of the route will be set to 500
• CRoute 11.1.0.0/16 can pass node 10, and its cost is set to 300
• DAny routes that do not pass through node 10 will be rejected.

• A
  6% (3)
• B
  12% (6)
• C
  78% (40)
• D
  4% (2)

Explanation

Option C is correct because route-policy nodes are processed sequentially, and when a route matches a permit node, the associated apply actions execute and processing immediately stops - it does not cascade to subsequent nodes. Route 11.1.0.0/16 matches the if-match ip-prefix 1 condition in node 10 (since ip-prefix 1 permits exactly 11.1.0.0/16), so the apply cost 300 action is applied and the route exits the policy.

Why the distractors are wrong:

• A is wrong because after a route matches a permit node, processing halts - 11.1.0.0/16 never reaches node 20.
• B (cost = 500) is wrong for the same reason; costs from node 10 and node 20 are not additive - only one node's actions apply.
• D is wrong because node 20 is a permit node with no if-match condition, so it acts as a catch-all - any route that misses node 10 will match node 20 and get cost 200, not be rejected.

Memory tip: Think of route-policy nodes like an if / else if chain - the first matching permit node wins and the rest are skipped; only a deny node or falling off the end of the policy causes rejection.

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