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H12-821_V1.0 · Question #1126

See the following figure. All routers on the network run IS-IS and are in an area 49.0001. By referring to the LSDB of R1, the Level-2 DIS is. (the device name, for example, R1.) A. R1 B. R2 C. R3…

The correct answer is A. R1. R1 is the Level-2 DIS because, in IS-IS DIS election on a broadcast segment, the router with the highest interface priority wins; if priorities are equal, the highest SNPA (MAC address) is the tiebreaker. In the figure, R1 holds the highest election metric on that LAN segment…

IPv4 Routing Technologies

Question

See the following figure. All routers on the network run IS-IS and are in an area 49.0001. By referring to the LSDB of R1, the Level-2 DIS is. (the device name, for example, R1.) A. R1 B. R2 C. R3 D. R4

Options

  • AR1
  • BR2
  • CR3
  • DR4

How the community answered

(61 responses)
  • A
    75% (46)
  • B
    7% (4)
  • C
    3% (2)
  • D
    15% (9)

Explanation

R1 is the Level-2 DIS because, in IS-IS DIS election on a broadcast segment, the router with the highest interface priority wins; if priorities are equal, the highest SNPA (MAC address) is the tiebreaker. In the figure, R1 holds the highest election metric on that LAN segment, and its LSDB confirms this: you will see a pseudonode LSP with R1's System ID and a non-zero circuit ID (e.g., R1.01-00), which only the DIS generates.

Why the distractors are wrong: R2, R3, and R4 each have a lower interface priority or a lower MAC address than R1, so they lose the election. A non-DIS router does not originate a pseudonode LSP - it only has its own node LSP - so their System IDs will not appear as a pseudonode entry in R1's LSDB.

Memory tip: "The DIS owns the pseudonode - look for the .01 LSP in the LSDB to identify who won the election. Highest priority → highest MAC → winner."

Topics

#IS-IS protocol#DIS election#Link State Database#Level-2 routing

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