H12-323_V2.0 · Question #44
In WLAN network, according to different channel bundling methods, the channel working bandwidth can be divided into several different types: 40MHz+, 40 MHz, 80 MHz, 80+80 MHZ and 160MHz. Which of…
The correct answer is B. 80MHz is to bundle two consecutive 40MHZ channels together and select one of the four 20MHz. Option B is correct because an 80MHz channel is formed by bundling two consecutive (contiguous) 40MHz channels, which together span four 20MHz sub-channels, and the primary channel is designated as one of those four 20MHz sub-channels - not forced to the highest frequency. Why…
Question
In WLAN network, according to different channel bundling methods, the channel working bandwidth can be divided into several different types: 40MHz+, 40 MHz, 80 MHz, 80+80 MHZ and 160MHz. Which of the following descriptions about the operating bandwidth of an 80MHz channel is correct?
Options
- A80MHz is to bundle two consecutive 40MHZ channels together and select the higher frequency
- B80MHz is to bundle two consecutive 40MHZ channels together and select one of the four 20MHz
- C80MHz is to bundle two discontinuous 40MHZ channels together and select the higher frequency
- D80MHz is to bundle two discontinuous 40MHZ channels together and select one of the four
How the community answered
(14 responses)- A14% (2)
- B71% (10)
- C7% (1)
- D7% (1)
Explanation
Option B is correct because an 80MHz channel is formed by bundling two consecutive (contiguous) 40MHz channels, which together span four 20MHz sub-channels, and the primary channel is designated as one of those four 20MHz sub-channels - not forced to the highest frequency.
Why the distractors fail:
- A is wrong because while it correctly identifies the channels as consecutive, it incorrectly states the primary channel is "the higher frequency" - the primary can be any of the four 20MHz sub-channels.
- C is wrong on both counts: 80MHz requires consecutive channels (not discontinuous), and it doesn't select "the higher frequency" - that's a confusion of two separate errors.
- D gets the primary channel selection right ("one of the four") but incorrectly describes the channels as discontinuous - that description belongs to the 80+80MHz mode, which deliberately uses two separate, non-adjacent 80MHz blocks.
Memory tip: Think of it as a spectrum of consecutiveness - 80MHz is a single contiguous block of four 20MHz channels (consecutive), while 80+80MHz is what you get when you break that into two separate pieces (discontinuous). If the answer mentions discontinuous channels for plain "80MHz," it's describing the plus variant (80+80), not standard 80MHz.
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