In the wireless coverage scenarios of wards and clinics, engineers proposed two network planning solutions as shown in the figure. Which of the following descriptions of these two solutions are…

Question

Exhibit

Options

• AIf the walls between rooms are brick walls, it is recommended to use solution A, which is to place
• BIf the walls between rooms are brick walls, it is recommended to use solution A, which is to place
• CIf the wall between the rooms is a gypsum wall, it is recommended to use solution B, one AP or
• DIf the walls between the rooms are plaster walls, it is recommended to use solution B, where one

• B
  6% (1)
• C
  12% (2)
• D
  82% (14)

Explanation

Option D is correct because gypsum (plaster) walls have low RF signal attenuation - radio waves pass through them with minimal loss, allowing a single AP to effectively cover multiple adjacent rooms. Solution B, which positions one AP to serve several rooms, is the efficient and cost-effective choice when wall materials offer little resistance to signal propagation.

Options A and B are incorrect because they recommend Solution A for brick walls with flawed or incomplete reasoning - brick walls have high RF attenuation, which means signals are heavily blocked; the correct response to brick walls is actually to place APs inside or directly adjacent to each room (Solution A), not to rely on signal penetration. The choices appear to state this but are likely wrong in their supporting detail or label the solutions incorrectly.

Option C is wrong because, while it correctly identifies gypsum walls, it likely recommends the wrong solution or states an incorrect number of APs - gypsum walls support Solution B (fewer APs, wider coverage), not a per-room approach.

Memory tip: Think of it as "Hard wall = Hard to penetrate = more APs (Solution A); Soft wall = Signal flows freely = fewer APs (Solution B)." Brick = hard material = dense AP deployment; Plaster/Gypsum = soft material = one AP, multiple rooms.

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