For the 3 APs deployed on the first floor, the channels from left to right are 1, 6, and 11 respectively. At this time, the channels of the 3 APs deployed on the 2nd floor should be divided into ()?

Question

Options

• A1, 6, 11
• B2, 7, 12
• C6, 11, 1
• D11, 6, 1

• A
  4% (1)
• B
  13% (3)
• C
  79% (19)
• D
  4% (1)

Explanation

Option C (6, 11, 1) is correct because it offsets the channel sequence by one position relative to the floor below, ensuring that no second-floor AP shares a channel with the first-floor AP directly beneath it -- the primary source of inter-floor interference. Channels 6, 11, and 1 are still all drawn from the three non-overlapping 2.4 GHz channels, so horizontal co-channel interference between adjacent second-floor APs is also avoided.

Option A (1, 6, 11) is wrong because it duplicates the first floor exactly, meaning every AP sits directly above another AP on the same channel, maximizing co-channel interference between floors. Option D (11, 6, 1) is wrong because the middle AP on floor 2 would use channel 6, which is the same channel as the AP directly below it on floor 1. Option B (2, 7, 12) is wrong because those are not the standard non-overlapping channels in 2.4 GHz; channels 2, 7, and 12 overlap with their neighbors and would cause additional interference.

Memory tip: Picture the floor 1 sequence (1, 6, 11) as a conveyor belt -- for floor 2, rotate it one step to the left to get (6, 11, 1). The same three non-overlapping channels are used, just shifted so nothing lines up vertically.

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