In order to obtain better coverage effect, how can the AP signal pass through the wall as much as possible?

Question

Options

• Avertical
• BParallel
• C45?
• D60?

• A
  74% (20)
• B
  15% (4)
• C
  4% (1)
• D
  7% (2)

Explanation

Vertical (perpendicular) incidence minimizes the effective path length through the wall material. When a signal hits a wall at 90°, it travels through only the wall's actual thickness - the shortest possible path. This means less material to attenuate the signal, resulting in maximum signal strength on the other side.

Why the distractors are wrong:

• B (Parallel): A signal traveling parallel to the wall never penetrates it at all - it skims the surface and provides no through-wall coverage.
• C (45°) and D (60°): Oblique angles force the signal to travel through a longer diagonal path inside the wall (effective thickness = wall_thickness ÷ cos(angle)), increasing attenuation compared to a straight-through path.

Memory tip: Think of cutting bread - slicing straight down (vertical/perpendicular) requires cutting through minimal material, while cutting at a diagonal means your blade travels through more bread. The signal behaves the same way: straight through the wall = least resistance.

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