D-UN-OE-23 · Question #8
A storage administrator has added multiple resources to a single density-based Host I/O Limit policy for the following storage resources: - LUN A:25GB - LUN B:25 GB - LUN C:50 GB - Density-Based…
The correct answer is A. 2000. Option A (2000 IOPS) is correct because a density-based limit applies the IOPS rate per GB of total storage, not per LUN or per policy. Adding the three LUNs gives 25 + 25 + 50 = 100 GB total, and 100 GB × 20 IOPS/GB = 2,000 IOPS. Why the distractors are wrong: C (60) confuses…
Question
A storage administrator has added multiple resources to a single density-based Host I/O Limit policy for the following storage resources:
- LUN A:25GB
- LUN B:25 GB
- LUN C:50 GB
- Density-Based Limit:20 IOPS
What is the total IOPS set by this policy?
Options
- A2000
- B500
- C60
- D1000
How the community answered
(31 responses)- A84% (26)
- B3% (1)
- C3% (1)
- D10% (3)
Explanation
Option A (2000 IOPS) is correct because a density-based limit applies the IOPS rate per GB of total storage, not per LUN or per policy. Adding the three LUNs gives 25 + 25 + 50 = 100 GB total, and 100 GB × 20 IOPS/GB = 2,000 IOPS.
Why the distractors are wrong:
- C (60) confuses density-based with a flat per-LUN limit - multiplying 3 LUNs × 20 IOPS ignores capacity entirely.
- D (1000) only accounts for the largest LUN (50 GB × 20 = 1,000), missing the other two.
- B (500) applies the rate to a single 25 GB LUN, as if only one resource were in the policy.
Memory tip: Think of "density" like density in physics - it's always rate × quantity (IOPS/GB × total GB). When multiple resources share one density-based policy, sum all their capacities first, then multiply by the density limit.
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