CSSGB · Question #44
Calculate the theoretical process yield using the normal distribution. Is this a reasonable calculation? If yes, why? If no, why not? Answer: ZLSL= (5.95 - 6.024)/ 0.01139 = -6.4969, hence, P( X < -6.
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Question
Calculate the theoretical process yield using the normal distribution. Is this a reasonable calculation? If yes, why? If no, why not? Answer:
ZLSL= (5.95 – 6.024)/ 0.01139 = -6.4969, hence, P( X < -6.4969) = 0.0000 ZUSL= (6.05 – 6.024)/ 0.01139 = 2.2827, hence, P( X > -2.2827) = 0.0112 P (5.95 ≤ X ≤ 6.05) = 0.0000 + 0.0112 = 0.0112 The above calculation is not reasonable because the process is not in statistical control. The above calculation is not reasonable because the process is not in statistical control.
Options
- AZLSL= (5.95 - 6.024)/ 0.01139 = -6.4969, hence, P( X < -6.4969) = 0.0000 ZUSL= (6.05 - 6.024)/ 0.01139 = 2.2827, hence, P( X > -2.2827) = 0.0112 P (5.95 ≤ X ≤ 6.05) = 0.0000 + 0.0112 = 0.0112 The above calculation is not reasonable because the process is not in statistical control. The above calculation is not reasonable because the process is not in stati
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