There will be 100 concurrent users streaming video to their laptops. A 30/70 split between 2.4 Ghz and 5 Ghz will be used. Roughly how many APs (rounded to the nearest whole number) are needed based…

The correct answer is C. 4. Option C (4 APs) is correct because the standard rule of thumb for client-based AP sizing is 25 clients per AP. With 100 concurrent users, 100 ÷ 25 = exactly 4 APs. The 30/70 band split (30 users on 2.4 GHz, 70 on 5 GHz) corroborates this: 2.4 GHz radios support roughly 14…

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Question

There will be 100 concurrent users streaming video to their laptops. A 30/70 split between 2.4 Ghz and 5 Ghz will be used. Roughly how many APs (rounded to the nearest whole number) are needed based on client count?

Options

How the community answered

(23 responses)

A
4% (1)
B
17% (4)
C
74% (17)
D
4% (1)

Explanation

Option C (4 APs) is correct because the standard rule of thumb for client-based AP sizing is 25 clients per AP. With 100 concurrent users, 100 ÷ 25 = exactly 4 APs. The 30/70 band split (30 users on 2.4 GHz, 70 on 5 GHz) corroborates this: 2.4 GHz radios support roughly 14 clients each (30 ÷ 14 ≈ 3 radios), while 5 GHz radios support ~25 clients each (70 ÷ 25 = 2.8 → 3 radios), blending to a 4-AP total when accounting for dual-band coverage overlap.

Why the distractors are wrong: A (2 APs) and B (3 APs) both under-provision - 2 APs can only reliably serve ~50 clients and 3 APs ~75, leaving insufficient headroom for video streaming load. D (5 APs) over-provisions based on the client count math; 5 APs would be a throughput-driven answer, not a client-count-driven one.

Memory tip: Anchor on the "25 rule" - divide your total client count by 25 to get your AP count. 100 ÷ 25 = 4. If an exam question says "based on client count," that's your formula.

Topics

#AP capacity planning#dual-band wireless#client density#wireless dimensioning

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