One thousand concurrent users stream video to their laptops. A 30/70 split between 2.4 GHz and 5 GHz is used. Based on client count, how many APs (rounded to the nearest whole number) are needed?

The correct answer is B. 28. Option B (28) is correct because the 5 GHz band drives the AP requirement. With 1,000 users at a 30/70 split, 700 users land on 5 GHz and 300 on 2.4 GHz. Using the standard design limit of 25 clients per AP, the 5 GHz side requires 700 ÷ 25 = 28 APs exactly - and since these…

Cisco Meraki Wireless Solutions

Question

Exhibit

Options

How the community answered

(43 responses)

A
5% (2)
B
74% (32)
C
14% (6)
D
7% (3)

Explanation

Option B (28) is correct because the 5 GHz band drives the AP requirement. With 1,000 users at a 30/70 split, 700 users land on 5 GHz and 300 on 2.4 GHz. Using the standard design limit of 25 clients per AP, the 5 GHz side requires 700 ÷ 25 = 28 APs exactly - and since these are dual-band APs, those same 28 units cover the 300 2.4 GHz clients (12 APs worth) with room to spare.

A (26) is wrong because 26 APs at 25 clients each only supports 650 clients on 5 GHz, leaving 50 users unserved. C (30) and D (32) are both overestimates - they result from mistakenly applying the 30-client-per-AP 2.4 GHz limit to the 5 GHz band, or from adding both band requirements as though they were independent AP counts instead of recognizing that dual-band APs serve both radios simultaneously.

Memory tip: Let the majority band do the math. In a 30/70 split, 70% × 1,000 = 700 clients on 5 GHz; divide by 25 (5 GHz capacity limit) and you get the AP count directly - no summing, no adding padding.

Topics

#AP capacity planning#band distribution#client density#wireless design

Community Discussion

No community discussion yet for this question.

Full 500-220 Practice