Refer to the exhibit. An engineer must pull the interface detail from multiple devices in the network and print out the management IP for the devices based on the JSON responses. VLAN 100 is present o

Question

Exhibits

Options

• Aprint(json.dumps["TABLE_intf"]["ROW_intf"][2]["prefix"])
• Bprint(json_object["TABLE_intf"]["ROW_intf"][1]["prefix"])
• Cprint(json_object["TABLE_intf"]["ROW_intf"][0]["prefix"])
• Dprint(json.dumps["TABLE_intf"]["ROW_intf"]["prefix"])

• A
  7% (3)
• B
  15% (6)
• C
  76% (31)
• D
  2% (1)

Explanation

Explanation

Option C is correct because json_object is the properly parsed Python dictionary (created via json.loads()), and VLAN 100 - being the first interface entry in the JSON response - is located at index [0] of the ROW_intf list, making json_object["TABLE_intf"]["ROW_intf"][0]["prefix"] the correct way to retrieve its IP address.

Why the distractors are wrong:

• Option A uses json.dumps with square brackets [], which is invalid - json.dumps is a function called with parentheses (), not a subscriptable dictionary object.
• Option B uses index [1], which would point to the second interface in the list, not VLAN 100 (the first/management interface).
• Option D uses json.dumps (same invalid syntax as A) and also skips the list index entirely, which would cause a TypeError since ROW_intf is a list, not a dictionary.

Memory Tip: Remember "dumps = strings, loads = objects" - json.dumps() converts a Python object to a JSON string, so you can't index into it like a dictionary. Always use your parsed json_object variable, and recall that Python lists are zero-indexed, so the first item is always [0].

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