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EC-Council

312-50V11 · Question #623

An nmap command that includes the host specification of 202.176.56-57.* will scan _______ number of hosts.

The correct answer is C. 512. The nmap wildcard '*' expands to all 256 values (0-255) for that octet. With two third-octet values (56 and 57), the total host count is 256 x 2 = 512.

Scanning Networks

Question

An nmap command that includes the host specification of 202.176.56-57.* will scan _______ number of hosts.

Options

  • A2
  • B256
  • C512
  • DOver 10, 000

How the community answered

(54 responses)
  • A
    9% (5)
  • B
    4% (2)
  • C
    83% (45)
  • D
    4% (2)

Why each option

The nmap wildcard '*' expands to all 256 values (0-255) for that octet. With two third-octet values (56 and 57), the total host count is 256 x 2 = 512.

A2

2 would be the count if only the two third-octet values were counted while ignoring the wildcard fourth octet expansion.

B256

256 would be correct for a single subnet wildcard like 202.176.56.*, but the range 56-57 doubles that count.

C512Correct

In nmap target specification, the range '56-57' selects two values for the third octet, and the wildcard '*' expands the fourth octet to all 256 addresses (0 through 255). Multiplying 2 third-octet values by 256 fourth-octet values yields exactly 512 unique host addresses that nmap will scan.

DOver 10, 000

Over 10,000 hosts would require a much broader range specification; two /24-equivalent ranges produce only 512 addresses.

Concept tested: Nmap target specification range and wildcard expansion

Source: https://nmap.org/book/man-target-specification.html

Topics

#nmap#host specification#IP range#wildcard

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