312-50V10 · Question #478
What is the approximate cost of replacement and recovery operation per year of a hard drive that has a value of $300 given that the technician who charges $10/hr would need 10 hours to restore OS…
The correct answer is D. $146. This question requires calculating SLE, then applying an assumed ARO of 1/3 (once every three years for hard drives) to derive the ALE.
Question
What is the approximate cost of replacement and recovery operation per year of a hard drive that has a value of $300 given that the technician who charges $10/hr would need 10 hours to restore OS and Software and needs further 4 hours to restore the database from the last backup to the new hard disk? Calculate the SLE, ARO, and ALE. Assume the EF = 1 (100%).
Options
- A$440
- B$100
- C$1320
- D$146
How the community answered
(20 responses)- A5% (1)
- B10% (2)
- C25% (5)
- D60% (12)
Why each option
This question requires calculating SLE, then applying an assumed ARO of 1/3 (once every three years for hard drives) to derive the ALE.
This value of $440 equals the raw SLE (asset plus labor cost) and ignores the ARO adjustment needed to produce an annualized figure.
This value of $100 corresponds only to the labor cost (10 hours x $10) without including the drive replacement cost or the ARO.
This value of $1320 is not derivable from the given figures using standard SLE/ARO/ALE formulas.
SLE equals asset value times EF: $300 x 1 = $300 for the drive, plus recovery labor of 14 hours x $10 = $140, giving SLE = $440. Hard drives are commonly assumed to fail roughly once every three years (ARO = 1/3), so ALE = $440 x (1/3) = approximately $146. This figure represents the annualized cost accounting for the realistic frequency of failure.
Concept tested: Risk quantification using SLE, ARO, and ALE formulas
Source: https://learn.microsoft.com/en-us/security/adoption/secure-methodology
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