312-49 · Question #219
Given the drive dimensions as follows and assuming a sector has 512 bytes, what is the capacity of the described hard drive? 22,164 cylinders/disk 80 heads/cylinder 63 sectors/track
The correct answer is A. 53.26 GB. Hard drive capacity is calculated using the CHS (Cylinders Ã- Heads Ã- Sectors) formula: Capacity = Cylinders Ã- Heads Ã- Sectors per track Ã- Bytes per sector. Calculation: 22,164 Ã- 80 Ã- 63 Ã- 512 = 57,193,758,720 bytes. Converting to binary gigabytes (GiB): 57,193,758,720 ÷ 1
Question
Given the drive dimensions as follows and assuming a sector has 512 bytes, what is the capacity of the described hard drive? 22,164 cylinders/disk 80 heads/cylinder 63 sectors/track
Options
- A53.26 GB
- B57.19 GB
- C11.17 GB
- D10 GB
How the community answered
(55 responses)- A73% (40)
- B7% (4)
- C16% (9)
- D4% (2)
Explanation
Hard drive capacity is calculated using the CHS (Cylinders Ã- Heads Ã- Sectors) formula: Capacity = Cylinders Ã- Heads Ã- Sectors per track Ã- Bytes per sector. Calculation: 22,164 Ã- 80 Ã- 63 Ã- 512 = 57,193,758,720 bytes. Converting to binary gigabytes (GiB): 57,193,758,720 ÷ 1,073,741,824 (1024³) ≈ 53.26 GB. Note that if you divide by 1,000,000,000 (decimal GB) you get ~57.19 GB (answer B), which is why both values appear as choices. Storage manufacturers often use decimal GB, but in forensics and OS contexts, binary GB (GiB) is standard, yielding 53.26 GB as the correct answer.
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