nerdexam
EC-CouncilEC-Council

312-49 · Question #21

312-49 Question #21: Real Exam Question with Answer & Explanation

The correct answer is C: 6 Sectors. A standard hard disk sector holds 512 bytes. To find the number of sectors needed for a 2600-byte file, divide the file size by the sector size: 2600 ÷ 512 = 5.078 sectors. Since partial sectors cannot be allocated, the OS rounds up to the next whole sector. Therefore, 6 full se

Submitted by chiamaka_o· Apr 18, 2026Disk Forensics

Question

If a file (readme.txt) on a hard disk has a size of 2600 bytes, how many sectors are normally allocated to this file?

Options

  • A4 Sectors
  • B5 Sectors
  • C6 Sectors
  • D7 Sectors

Explanation

A standard hard disk sector holds 512 bytes. To find the number of sectors needed for a 2600-byte file, divide the file size by the sector size: 2600 ÷ 512 = 5.078 sectors. Since partial sectors cannot be allocated, the OS rounds up to the next whole sector. Therefore, 6 full sectors are allocated to store the file, even though the last sector is only partially used. This unused space at the end of the last sector is called 'slack space'.

Topics

#File Systems#Disk Allocation#Sector Size#Storage Fundamentals

Community Discussion

No community discussion yet for this question.

Full 312-49 PracticeBrowse All 312-49 Questions