300-820 · Question #93
A call is sent by Cisco UCM to Expressway with a URI of [email protected]. If (7508...) @expc1a\.pod8\.test\.lab.* is the pattern string, what would be the replacement string of the…
The correct answer is C. \[email protected]\.test\.lab. In Expressway transforms, the pattern uses regex capturing groups defined by parentheses. The pattern (7508...) captures 8 digits starting with 7508 as group 1. In the replacement string, \1 is the back-reference that substitutes the captured group (e.g., '75080001'). The goal…
Question
A call is sent by Cisco UCM to Expressway with a URI of [email protected]. If (7508...) @expc1a.pod8.test.lab.* is the pattern string, what would be the replacement string of the transform in Expressway to re-write the call so that it becomes [email protected]?
Options
- A\[email protected].@
- B\[email protected]\lab.*
- C\[email protected]
- D\[email protected].!
How the community answered
(46 responses)- A9% (4)
- B2% (1)
- C85% (39)
- D4% (2)
Explanation
In Expressway transforms, the pattern uses regex capturing groups defined by parentheses. The pattern (7508...) captures 8 digits starting with 7508 as group 1. In the replacement string, \1 is the back-reference that substitutes the captured group (e.g., '75080001'). The goal is to produce [email protected]. Option C, \[email protected]\.test\.lab, accomplishes this: \1 inserts the captured number, and the rest is the literal new domain. In a replacement string context, backslash-dot (\.) is interpreted as a literal dot, and an unescaped dot is also treated as a literal character (unlike in the search pattern). Options A and D contain extraneous trailing characters (@ and !). Option B uses \lab (missing the dot before 'lab') and an unnecessary .* suffix, making it incorrect.
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