A 802.11n implementation is being discussed. Users are satisfied with the potential 300- 450 Mbps throughput of new 802.11n APs. Which three bandwidth requirements are used to calculate per client…

Question

Options

• A300 Mbps throughput is the client max for 2.4-GHz radio.
• B450 Mbps throughput is the client max for 5-GHz radio.
• C100 Mbps AP Ethernet switch port is a potential bottleneck.
• DCleanAir helps clear noise for 802.11n channel bonding to work.
• EChannel bonding on 5 GHz is required for a client to have a 300 Mbps WiFi link.
• FThe remaining bandwidth is divided per device when more clients are connected to one AP.

• A
  14% (8)
• B
  9% (5)
• C
  73% (41)
• D
  4% (2)

Explanation

Three key factors determine real per-client bandwidth in an 802.11n network. (C) A 100 Mbps Ethernet uplink on the AP is a hard ceiling - even if the wireless link is 300 Mbps, the wired backhaul limits total AP throughput to 100 Mbps. (E) 802.11n requires 40 MHz channel bonding (two adjacent 20 MHz channels) to reach 300 Mbps; without bonding the maximum is 150 Mbps per stream, and channel bonding is practical only on 5 GHz where enough non-overlapping 40 MHz channels exist. (F) Wi-Fi is a shared half-duplex medium - all clients on one AP share total available bandwidth, so more clients mean less bandwidth per client. The 450 Mbps figure requires three spatial streams (3×3 MIMO), which is not a universal client capability.

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