Refer to the exhibit. An engineer must apply IP addressing to five new WAN sites and choses the new subnets pictured. The previous administrator applied the addressing at Headquarters. Whitch option…

The correct answer is E. 10.0.64.0/18. The five existing WAN sites plus three additional sites equals eight total subnets to accommodate. Based on the exhibit's addressing in the 10.0.64.0 range, a /18 prefix (10.0.64.0/18) covers the address space from 10.0.64.0 through 10.0.127.255 - providing 64 blocks sufficient…

Advanced Addressing and Routing Solutions

Question

Refer to the exhibit. An engineer must apply IP addressing to five new WAN sites and choses the new subnets pictured. The previous administrator applied the addressing at Headquarters. Whitch option is the minimum summary range to cover the existing WAN sites while also allowing for three additional WAN sites of the same size, for future growth?

Exhibits

Options

A10.0.60.0/18
B10.0.64.0/21
C10.0.64.0/17
D10.0.0.0/17
E10.0.64.0/18

How the community answered

(61 responses)

A
18% (11)
B
2% (1)
C
5% (3)
D
10% (6)
E
66% (40)

Explanation

The five existing WAN sites plus three additional sites equals eight total subnets to accommodate. Based on the exhibit's addressing in the 10.0.64.0 range, a /18 prefix (10.0.64.0/18) covers the address space from 10.0.64.0 through 10.0.127.255 - providing 64 blocks sufficient for 8 or more same-sized subnets. A /21 (option B) is too small to cover all required subnets. A /17 (options C/D) would work but is not the minimum (smallest) summary. The /18 in option E is the most specific summary that covers all existing and three future sites.

Topics

#IP summarization#VLSM#WAN addressing#subnet calculation

Community Discussion

No community discussion yet for this question.

Full 300-320 Practice