You are assigned the network of 192.168.1.0/24. You want to split the network into four subnets that are all the same size. Which three statements about the first subnet that you create are true?…

Question

Options

• AThe subnet mask is 255.255.255.192
• BThe last host IP address is 192.168.164
• CThe subnet mask is 255.255.255.224
• DThe subnet has up to 64 hosts
• EThe last host IP address is 192.168.1.62
• FThe subnet has up to 62 hosts

• A
  94% (29)
• B
  3% (1)
• D
  3% (1)

Explanation

To divide 192.168.1.0/24 into 4 equal subnets, you need to borrow 2 bits (2² = 4), creating a /26 prefix. The subnet mask for /26 is 255.255.255.192 (confirming A is correct). Each /26 subnet contains 64 total addresses (2^6 = 64), but 2 are reserved (network address and broadcast), leaving 62 usable host addresses (confirming F is correct; D is wrong because '64 hosts' includes unusable addresses). The first subnet is 192.168.1.0/26: network address = 192.168.1.0, first usable host = 192.168.1.1, last usable host = 192.168.1.62, broadcast = 192.168.1.63 (confirming E is correct). Option B is incorrect ('192.168.164' is not a valid IP address and appears to be a typo/error). Option C (255.255.255.224 = /27) would create 8 subnets, not 4.

No community discussion yet for this question.