200-301 · Question #880
The address block 192.168.32.0/24 must be subnetted into smaller networks. The engineer must meet these requirements: - Create 8 new subnets. - Each subnet must accommodate 30 hosts. - Interface VLAN
The correct answer is C. no switchport. Requirement is 8 networks with 30 hosts 255.255.255.0 = 11111111.11111111.11111111.00000000 8 networks = 1111 with increment of 16 which is less host number than require. 30 hosts = 11100000 with increment of 32 255.255.255.224 or 11111111.11111111.11111111.11100000 8 networks fo
Question
The address block 192.168.32.0/24 must be subnetted into smaller networks. The engineer must meet these requirements:
- Create 8 new subnets.
- Each subnet must accommodate 30 hosts.
- Interface VLAN 10 must use the last usable IP in the first new
subnet.
- A Layer 3 interface is used.
Which configuration must be applied to the interface?
Options
- Ano switchport mode trunk
- Bswitchport
- Cno switchport
- Dno switchport mode access
How the community answered
(44 responses)- A18% (8)
- B7% (3)
- C70% (31)
- D5% (2)
Explanation
Requirement is 8 networks with 30 hosts 255.255.255.0 = 11111111.11111111.11111111.00000000 8 networks = 1111 with increment of 16 which is less host number than require. 30 hosts = 11100000 with increment of 32 255.255.255.224 or 11111111.11111111.11111111.11100000 8 networks for /27 are 0,32,64,96,128,160,192,224
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