200-201 · Question #364
Drag and Drop Question Refer to the exhibit. Drag and drop the element names from the left onto the corresponding pieces of the PCAP file on the right. Answer:
The correct answer is source address -> 10.0.2.15; source port -> 50588; destination port -> 443; destination address -> 192.124.249.9; Network Protocol -> TCP; Transport Protocol -> Internet Protocol v4; Application Protocol -> TLS v1.2. In a PCAP file, the source address (10.0.2.15) and destination address (192.124.249.9) are the IP addresses found in the Internet Protocol v4 (Network Protocol) header, while source port (50588) and destination port (443) are TCP (Transport Protocol) fields. TLS v1.2 is the…
Question
Drag and Drop Question Refer to the exhibit. Drag and drop the element names from the left onto the corresponding pieces of the PCAP file on the right. Answer:
Exhibit
Answer Area
Drag items
Correct arrangement
- source address -> 10.0.2.15
- source port -> 50588
- destination port -> 443
- destination address -> 192.124.249.9
- Network Protocol -> TCP
- Transport Protocol -> Internet Protocol v4
- Application Protocol -> TLS v1.2
Explanation
In a PCAP file, the source address (10.0.2.15) and destination address (192.124.249.9) are the IP addresses found in the Internet Protocol v4 (Network Protocol) header, while source port (50588) and destination port (443) are TCP (Transport Protocol) fields. TLS v1.2 is the Application Protocol operating over TCP port 443, which is the standard HTTPS/TLS port. The labels 'Network Protocol' and 'Transport Protocol' are swapped in the correct arrangement - Internet Protocol v4 is the Network Layer (Layer 3) protocol, and TCP is the Transport Layer (Layer 4) protocol, which aligns with the OSI model.
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