Refer to the exhibit. The company uses EIGRP as the routing protocol. Which path will packets take from a host on an 192.168.10.192/26 network to a host on the LAN attached to router R1?

The correct answer is D. The path of the packets will be R3 to R1. EIGRP selects paths based on its composite metric, which uses bandwidth and delay by default. In this topology, EIGRP calculates that the direct link from R3 to R1 yields a lower (better) composite metric than the path through R2 (R3 → R2 → R1). Even though both paths reach the 1

Implement an EIGRP Based Solution

Question

Refer to the exhibit. The company uses EIGRP as the routing protocol. Which path will packets take from a host on an 192.168.10.192/26 network to a host on the LAN attached to router R1?

Exhibit

Options

AThe path of the packets will be R3 to R2 to R1
BThe path of the packets will be R3 to R1 to R2
CThe path of the packets will be both R3 to R2 to R1 and R3 to R1
DThe path of the packets will be R3 to R1

How the community answered

(49 responses)

A
4% (2)
B
6% (3)
C
10% (5)
D
80% (39)

Explanation

EIGRP selects paths based on its composite metric, which uses bandwidth and delay by default. In this topology, EIGRP calculates that the direct link from R3 to R1 yields a lower (better) composite metric than the path through R2 (R3 → R2 → R1). Even though both paths reach the 192.168.10.192/26 network, EIGRP installs only the single best path unless equal-cost load balancing applies. Since the direct path is superior, all packets travel R3 → R1.

Topics

#EIGRP#path selection#metric calculation#routing table

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