You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while providing the maximum number of subnets. Which network address and subnet mask…

The correct answer is B. 192.168.252.8 255.255.255.248. The requirement is to fit all three web servers on the same subnet while maximizing the number of available subnets. A /29 mask (255.255.255.248) provides 6 usable host addresses per subnet (2^3 – 2 = 6), which is sufficient for 3 servers. Applied to a /24 base network, a /29…

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Question

You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while providing the maximum number of subnets. Which network address and subnet mask meet this requirement?

Exhibit

Options

A192.168.252.0 255.255.255.252
B192.168.252.8 255.255.255.248
C192.168.252.8 255.255.255.252

How the community answered

(34 responses)

A
12% (4)
B
82% (28)
C
6% (2)

Explanation

The requirement is to fit all three web servers on the same subnet while maximizing the number of available subnets. A /29 mask (255.255.255.248) provides 6 usable host addresses per subnet (2^3 – 2 = 6), which is sufficient for 3 servers. Applied to a /24 base network, a /29 yields 32 subnets-the maximum possible while still accommodating 3 hosts. Option A (255.255.255.252, /30) provides only 2 usable hosts per subnet, which cannot support 3 servers. Option C also uses /30 for the same reason and is equally insufficient. Option B (192.168.252.8/255.255.255.248) correctly identifies the 192.168.252.8/29 subnet (hosts .9–.14), which satisfies both constraints.

Topics

#subnetting#VLSM#subnet mask selection#host requirements

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