public interface EulerInterface { double getEulerValue(); } public class EulerLambda { public static void main(String[] args) { EulerInterface myEulerInterface = () -> 2.71828…

Question

Options

• AIt throws a runtime exception.
• BValue of Euler = 2.71828
• CThe code does not compile.
• DValue of Euler = "2.71828"

• A
  10% (2)
• B
  5% (1)
• C
  80% (16)
• D
  5% (1)

Explanation

Option C is correct because Java only permits one public type per .java source file. As written, both EulerInterface and EulerLambda are declared public - placing them in the same file violates this rule and the compiler rejects it immediately.

Why the distractors are wrong:

• B is what would print if the code were fixed (e.g., split into two files or one declaration made package-private) - the lambda syntax itself is valid since EulerInterface qualifies as a functional interface (one abstract method), so () -> 2.71828 is a legal implementation.
• A is wrong because the error is a compile-time constraint, never reaching the JVM where a runtime exception could be thrown.
• D is wrong on two counts: double values don't print with quotes, and again, the code never runs.

Memory tip: When you see multiple public type declarations shown together in a single code block, always check the "one public type per file" rule before analyzing logic - it's a frequent gotcha on Java certification exams.

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