Which of the following produces the same result as the given for loop? ``java for (int i = 1; i < 10; ++i) { System.out.println(i); } ``

Question

for (int i = 1; i < 10; ++i) {
 System.out.println(i);
}

Options

• AStream<Integer> nums1 = Stream.iterate(1, n -> n < 10, n + 2); forEach(System.out.println);
• BStream<Integer> nums2 = Stream.iterate(1, n -> n < 10, n + 1); forEach(System.out.println(n));
• CStream<Integer> nums3 = Stream.iterate(1, n -> n < 10, n + 1); forEach(System.out.println);
• DStream.iterate(1, n -> n < 10, n + 1).forEach(System.out.println);

• A
  9% (3)
• B
  84% (27)
• C
  3% (1)
• D
  3% (1)

Explanation

Option B correctly replicates the for loop because it uses Stream.iterate(1, n -> n < 10, n + 1), which starts at 1, stops before 10, and increments by 1 - matching i = 1, i < 10, and ++i exactly - and passes a valid consumer expression to forEach that prints each element.

Why the distractors fail:

• A is wrong because n + 2 increments by 2, producing 1, 3, 5, 7, 9 instead of 1 through 9.
• C uses the correct step (n + 1) but forEach(System.out.println) is invalid - forEach requires a Consumer<T>, and System.out.println without the method-reference operator (::) is not a valid consumer.
• D has the same forEach syntax problem as C; writing the chain on one line doesn't fix the missing ::.

Memory tip: Think of Stream.iterate's three arguments as matching the three parts of a for loop: (seed, condition, step) → (int i = 1, i < 10, ++i). And always remember that forEach needs a method reference (System.out::println) or a lambda (n -> System.out.println(n)) - never a bare method call.

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