Given the code fragment: final String str1 = "Java"; StringBuffer strBuf = new StringBuffer("Course"); UnaryOperator<String> s = (str2) -> str1.concat(str2); // line n1 UnaryOperator<String> c =…

Question

Options

• AVal:20 Val:40 Val:60
• BVal:10 Val:20 Val:30
• CA compilation error occurs.
• DVal: Val: Val:

• A
  78% (40)
• B
  6% (3)
• C
  14% (7)
• D
  2% (1)

Explanation

There appears to be an error in the provided correct answer. The code as written actually produces a compilation error (option C), not option A.

The code has two distinct compilation problems: first, the variable u is never declared - only s and c are defined, so u.apply(...) on line n2 references an undefined symbol; second, c.apply(strBuf) passes a StringBuffer to a UnaryOperator<String>, but StringBuffer is not a String, causing a type mismatch - Java generics are not covariant here and no implicit conversion exists. Options A, B, and D all describe runtime output, which is impossible to reach when the code won't compile; option D might tempt you if you assume concat or toLowerCase could return empty strings, but that reasoning is moot. The memory tip: whenever you see a lambda chain, trace the declared variable names carefully - if the code uses a name that was never assigned, it's a compile error before any logic runs.

Bottom line: The correct answer for this code is C, not A. If this is from an official exam source, the question was likely transcribed with errors (either u should be s, or the correct answer label is wrong).

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