Given the code fragment: List<String> cs = Arrays.asList("Java", "Java EE", "Java ME"); // line n1 System.out.print(b); Which code fragment, when inserted at line n1, ensures false is printed?

Question

Options

• Aboolean b = cs.stream().findAny().get().equals("Java");
• Bboolean b = cs.stream().anyMatch(w -> w.equals("Java"));
• Cboolean b = cs.stream().findFirst().get().equals("Java");
• Dboolean b = cs.stream().allMatch(w -> w.equals("Java"));

• A
  3% (1)
• B
  10% (3)
• C
  17% (5)
• D
  70% (21)

Explanation

D is correct because allMatch returns true only if every element in the stream satisfies the predicate. Since the list contains "Java EE" and "Java ME" - which do not equal "Java" - allMatch short-circuits on the second element and returns false.

Why the distractors fail:

• A (findAny().get().equals("Java")) - findAny() on a sequential stream typically returns the first element, "Java", so the equals check is true.
• B (anyMatch(w -> w.equals("Java"))) - anyMatch returns true as soon as any element matches; "Java" is in the list, so it's true.
• C (findFirst().get().equals("Java")) - findFirst() always returns "Java" (the first element), making the comparison true.

Memory tip: Think of the prefix: allMatch = all or nothing. If even one element fails the test, the whole thing is false. When you see a mixed list and a strict single-value predicate, allMatch is your go-to for forcing false.

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