Given the code fragment: Path file = Paths.get ("courses.txt"); // line n1 Assume the courses.txt is accessible. Which code fragment can be inserted at line n1 to enable the code to print the…

Question

Options

• AList<String> s = Files.list(file); fc.stream().forEach (s -> System.out.println(s));
• BStream<String> fc = Files.readAllLines (file); fc.forEach (s -> System.out.println(s));
• CList<String> fc = Files.readAllLines (file); fc.stream().forEach (s -> System.out.println(s));
• DStream<String> fc = Files.list (file); fc.forEach (s -> System.out.println(s));

• A
  13% (3)
• B
  75% (18)
• C
  8% (2)
• D
  4% (1)

Explanation

Option B as stated does not actually compile - this question contains an error in the answer key. Files.readAllLines(Path) returns List<String>, not Stream<String>, so assigning it to Stream<String> fc causes a type mismatch at compile time. Option C is the genuinely correct answer: it correctly assigns Files.readAllLines(file) to List<String> fc, then calls .stream().forEach() to print each line.

Why each distractor fails:

• A - Files.list(Path) returns Stream<Path> (directory entries, not file lines), not List<String>; additionally the code references undeclared variable fc after declaring s.
• B - Files.readAllLines() returns List<String>, not Stream<String> - this is a compile-time type mismatch.
• D - Files.list(Path) lists directory contents as Stream<Path>, not file lines as Stream<String>; using it on a regular file to read text content is semantically and type-incorrect.

Memory tip: Link the method name to its return type - readAll**Lines** ends with the plural noun, so it returns a List; Files.lines() (the streaming variant) returns a Stream<String>. When you see Stream<String> on the left-hand side, the right-hand side must call Files.lines(), not Files.readAllLines().

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