Given the code fragment: List<Integer> nums = Arrays.asList( 10, 20, 8); System.out.println ( // line n1 ); Which code fragment must be inserted at line n1 to enable the code to print the maximum…

Question

Options

• Anums.stream().max(Comparator.comparing(a -> a)).get()
• Bnums.stream().max(Integer :: max).get()
• Cnums.stream().max()
• Dnums.stream().map(a -> a).max()

• A
  84% (21)
• B
  4% (1)
• C
  8% (2)
• D
  4% (1)

Explanation

Option A works because Stream.max() requires a Comparator argument, and Comparator.comparing(a -> a) creates a valid natural-order comparator by using the identity function as the key extractor - it compares each Integer by its own value, correctly returning Optional<Integer> which .get() unwraps to 20.

Option B compiles but violates the Comparator contract: Integer::max(a, b) always returns the larger value (always positive), so it never returns a negative number - meaning the comparator can never signal "less than," making the result unreliable.

Options C and D both fail to compile: Stream.max() has no zero-argument overload, so calling .max() without a Comparator is a compilation error regardless of what precedes it.

Memory tip: max() on a stream is not like Math.max() - it can't compare on its own and always needs a Comparator. When in doubt, reach for Comparator.comparing(...) or Comparator.naturalOrder() as safe, readable choices.

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