Given the code fragment: 1. ArrayList<Integer> list = new ArrayList<>(1); 2. list.add(1001); 3. list.add(1002); 4. System.out.println(list.get(list.size())); What is the result?

The correct answer is C. An exception is thrown at run time due to error on line 4. The code compiles fine. At runtime an IndexOutOfBoundsException is thrown when the second list item is added.

Working with Selected Classes from the Java API

Question

Given the code fragment: 1. ArrayList<Integer> list = new ArrayList<>(1); 2. list.add(1001); 3. list.add(1002); 4. System.out.println(list.get(list.size())); What is the result?

Options

ACompilation fails due to an error on line 1.
BAn exception is thrown at run time due to error on line 3
CAn exception is thrown at run time due to error on line 4
D1002

How the community answered

(51 responses)

A
16% (8)
B
4% (2)
C
73% (37)
D
8% (4)

Explanation

The code compiles fine. At runtime an IndexOutOfBoundsException is thrown when the second list item is added.

Topics

#ArrayList#IndexOutOfBoundsException#Java Collections#runtime errors

Community Discussion

No community discussion yet for this question.

Full 1Z0-803 Practice