Given: Which code fragment, when inserted at line 14, enables the code to print Mike Found?

This fragment contains a syntax error (`{{ }}`) and, even if corrected to `new Patient("Mike")`, it would create a new object instance. Without `equals()` overridden in `Patient` to compare content, `indexOf` would likely return -1 as it compares object references.

This fragment contains a syntax error (`patient("Mike")` instead of `new Patient("Mike")`). Even if fixed, it would create a new object instance, which typically would not be found by reference comparison if `equals()` is not overridden.

This fragment only creates a new `Patient` object `p` but does not perform an `indexOf` operation on the `ps` list or assign a value to a variable `f`, so it does not directly enable the desired print statement.

The `indexOf` method in Java's `List` interface, when called with an object `p2`, checks for object identity (using `==`) unless the `equals` method is overridden. If `p2` refers to an existing `Patient` object already added to the `ps` list, `indexOf(p2)` will correctly return its index, enabling the 'Mike Found' message.