Given the code fragment: List colors = new ArrayList(); colors.add("green"); colors.add("red"); colors.add("blue"); colors.add("yellow"); colors.remove(2); colors.add(3,"cyan"); System.out.print(color

The correct answer is A. [green, red, yellow, cyan]. First the list[green, red,blue, yellow]is build. The blue element is removed: [green, red,yellow] Finally the element cyan is added at then end of the list (index 3). [green, red, yellow, cyan]

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Question

Given the code fragment:

List colors = new ArrayList(); colors.add("green"); colors.add("red"); colors.add("blue"); colors.add("yellow"); colors.remove(2); colors.add(3,"cyan"); System.out.print(colors); What is the result?

Options

A[green, red, yellow, cyan]
B[green, blue, yellow, cyan]
C[green, red, cyan, yellow]
DAm IndexOutOfBoundsException is thrown at runtime

How the community answered

(47 responses)

A
83% (39)
B
4% (2)
C
11% (5)
D
2% (1)

Explanation

First the list[green, red,blue, yellow]is build. The blue element is removed: [green, red,yellow] Finally the element cyan is added at then end of the list (index 3). [green, red, yellow, cyan]

Topics

#ArrayList#collections#list operations#index-based operations

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