Given: public class Test { public static void main(String[] args) { int i = 1; do { if ( i % 2 == 0) continue; if (i == 5) break; System.out.print(i + "\t"); i++; } while (true); } } What is the resul

This is incorrect because the loop goes infinite after printing '1', it does not print '3'.

This is incorrect because `i` is never printed when it's an even number due to the `continue` statement.

This is incorrect because `1` is printed in the first iteration.

This is incorrect because `1` is printed only once, not infinite times, before `i` becomes `2` and the loop enters an infinite `continue` cycle.

In the first iteration, `i` is `1` (odd), so '1' is printed and `i` increments to `2`. In all subsequent iterations, `i` is `2` (even), which triggers the `if (i % 2 == 0) continue;` statement. The `continue` statement immediately skips the rest of the loop body, including `i++`, and jumps to the `while` condition. This causes `i` to remain `2` indefinitely, resulting in an infinite loop that prints '1' only once.