Given: Which two are possible outputs?

The correct answer is A. Option A D. Option D. The first println statement, System.out.println("Before if clause");, will always run. If Math.Random() > 0.5 then there is an exception. The exception message is displayed and the program terminates. If Math.Random() > 0.5 is false, then the second println statement runs as well

Using Loop Constructs

Question

Given:

Which two are possible outputs?

Exhibits

Options

AOption A
BOption B
COption C
DOption D

How the community answered

(33 responses)

A
58% (19)
B
27% (9)
C
15% (5)

Explanation

The first println statement, System.out.println("Before if clause");, will always run. If Math.Random() > 0.5 then there is an exception. The exception message is displayed and the program terminates. If Math.Random() > 0.5 is false, then the second println statement runs as well. Incorrect answers: B: The second println statement would not run. C: The first println statement will always run.

Topics

#control flow#conditional logic#loop execution#program output

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