An administrator is writing a Bash script that contains a loop that increments the value of the variable count with each loop iteration by 1. Which of the following should the administrator use?

The $count++ expression applies the C-style post-increment operator, which is recognized inside Bash arithmetic evaluation constructs such as (( $count++ )) or $(( $count++ )), incrementing the variable by 1 each iteration. It is the most concise and readable form matching standard increment notation used in many scripting and programming contexts. Among the provided choices, it correctly represents the post-increment pattern the question describes.

Single quotes suppress all variable expansion and command substitution in Bash, so Count='expr $count+1' assigns the literal string 'expr $count+1' to Count rather than computing a numeric result.

Bash treats spaces around '=' as argument separators outside arithmetic context, so 'Count = $count+1' is parsed as a command named 'Count' with '=' and '$count+1' as arguments, not an assignment.

While ((++count)) is valid Bash arithmetic syntax, it uses the pre-increment form which increments before returning the value, and the notation differs from the post-increment pattern referenced by the correct answer.