Which of the following would the security engineer set as the subnet mask for the servers below to utilize host addresses on separate broadcast domains? Server 1: 192.168.100.6 Server 2: 192.168.100.9

The correct answer is D. /29. A /29 subnet (255.255.255.248) creates blocks of 8 addresses. Server 1 (192.168.100.6) falls in the 192.168.100.0/29 block (.0–.7), and Server 2 (192.168.100.9) falls in the 192.168.100.8/29 block (.8–.15) - placing them in separate broadcast domains. Server 3 (192.169.100.20) is

Security architecture

Question

Which of the following would the security engineer set as the subnet mask for the servers below to utilize host addresses on separate broadcast domains? Server 1: 192.168.100.6 Server 2: 192.168.100.9 Server 3: 192.169.100.20

Options

A/24
B/27
C/28
D/29
E/30

How the community answered

(57 responses)

A
4% (2)
B
7% (4)
C
2% (1)
D
72% (41)
E
16% (9)

Explanation

A /29 subnet (255.255.255.248) creates blocks of 8 addresses. Server 1 (192.168.100.6) falls in the 192.168.100.0/29 block (.0–.7), and Server 2 (192.168.100.9) falls in the 192.168.100.8/29 block (.8–.15) - placing them in separate broadcast domains. Server 3 (192.169.100.20) is on a completely different network (192.169.x.x), so it is already isolated. A /28 block of 16 would put Servers 1 and 2 in the same subnet (.0–.15), failing the requirement. /29 is the largest (most host-efficient) mask that still separates all three servers into distinct broadcast domains.

Topics

#subnetting#CIDR notation#broadcast domains#network segmentation

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