SOA-C02 Question #223: Real Exam Question with Answer & Explanation

Question

An environment consists of 100 Amazon EC2 Windows instances. The Amazon CloudWatch agent is deployed and running on all EC2 Instances with a baseline configuration file to capture log files. There is a new requirement to capture the DHCP log files that exist on 50 of the instances. What is the MOST operationally efficient way to meet this new requirement?

Options

• ACreate an additional CloudWatch agent configuration file to capture the DHCP logs.
• BLog in to each EC2 instance with administrator rights.
• CRun the CloudWatch agent configuration file wizard on each EC2 instance.
• DRun the CloudWatch agent configuration file wizard on each EC2 instance and select the

Explanation

Option A is correct because the CloudWatch agent supports appending additional configuration files to the baseline configuration, allowing you to add DHCP log capture to only the 50 relevant instances without modifying or replacing the existing baseline config - this is the least disruptive, most scalable approach.

Why the distractors fail:

• B is wrong because manually logging into 50 instances to configure log collection is operationally expensive, error-prone, and doesn't scale - the entire point of the CloudWatch agent is to avoid this.
• C and D are wrong because running the configuration wizard on each instance individually defeats the purpose of centralized configuration management; it's tedious at scale and would likely overwrite or conflict with the existing baseline config rather than extend it.

Memory tip: Think of CloudWatch agent configs like CSS stylesheets - you can stack additional ones on top of the base without touching the original. "Additional config file" = additive, targeted, efficient. Any answer requiring you to touch every machine individually is almost always wrong in AWS operational efficiency questions.

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