The specification of disk drives used in a storage system lists an average of 200 read IOPS per drive. Which of the following should be expected of an 8 drive RAID 5 array?

This value is incorrect as it does not align with the standard RAID 5 read IOPS calculation of (N-1) * per-drive IOPS.

This value is incorrect as it does not align with the standard RAID 5 read IOPS calculation of (N-1) * per-drive IOPS.

In a RAID 5 array, one drive is used for parity, so an 8-drive array has 7 data drives available. For read operations, all data drives can contribute, thus the total read IOPS is calculated as (Number of drives - 1) * IOPS per drive, which is (8-1) * 200 = 7 * 200 = 1400 IOPS.

This value incorrectly assumes all 8 drives are contributing to data reads, disregarding the single parity drive in a RAID 5 configuration.