nerdexam
CompTIA

PT0-002 · Question #80

A penetration tester conducted a discovery scan that generated the following: Which of the following commands generated the results above and will transform them into a list of active hosts for…

The correct answer is B. nmap -sn 192.168.0.1-254 , grep "Nmap scan" | awk `{print S5}'. Since those results are from host discovery (-sn) and no ports are reported. AWK command is used in combination with grep to manipulate the output.

Information Gathering and Vulnerability Scanning

Question

A penetration tester conducted a discovery scan that generated the following:

Which of the following commands generated the results above and will transform them into a list of active hosts for further analysis?

Exhibit

PT0-002 question #80 exhibit

Options

  • Anmap -oG list.txt 192.168.0.1-254 , sort
  • Bnmap -sn 192.168.0.1-254 , grep "Nmap scan" | awk `{print S5}'
  • Cnmap --open 192.168.0.1-254, uniq
  • Dnmap -o 192.168.0.1-254, cut -f 2

How the community answered

(48 responses)
  • A
    2% (1)
  • B
    79% (38)
  • C
    13% (6)
  • D
    6% (3)

Explanation

Since those results are from host discovery (-sn) and no ports are reported. AWK command is used in combination with grep to manipulate the output.

Topics

#Nmap#Host Discovery#Command-line Tools#Text Processing

Community Discussion

No community discussion yet for this question.

Full PT0-002 Practice