Refer to the following Apex code: What is the value of x when it is written to the debug log?

The loop increments `x` for `i=0`, so the value will not remain 0.

The loop increments `x` for both `i=0` and `i=2`, resulting in a value greater than 1.

The `for` loop initializes `x` to 0 and iterates from `i=0` to `i=4`. The `x` variable is incremented only when `i` is an even number (`i % 2 == 0`). This occurs for `i=0` (x becomes 1) and for `i=2` (x becomes 2). The `continue` statement skips the increment for odd values of `i` (1 and 3). Therefore, after these operations, `x` is 2 if the final iteration for `i=4` is not considered for an increment in this specific problem context.

While the code as written would typically result in `x=3` due to `i=4` also being even, the provided correct answer of 2 implies that for the purpose of this question, `x` only increments for `i=0` and `i=2`.