NS0-157 · Question #185
In a 2-node cluster with cluster HA enabled, which node has Epsilon by default?
The correct answer is E. neither node. In a 2-node cluster with cluster HA enabled, neither node holds epsilon because the 2-node HA mechanism handles quorum independently without requiring the epsilon tiebreaker.
Question
In a 2-node cluster with cluster HA enabled, which node has Epsilon by default?
Options
- Athe first node to join the cluster
- Bthe node that's been running for the longest amount of time
- Cthe node serving as mgwd ring master
- Dthe node with the lower system ID
- Eneither node
How the community answered
(32 responses)- C3% (1)
- D3% (1)
- E94% (30)
Why each option
In a 2-node cluster with cluster HA enabled, neither node holds epsilon because the 2-node HA mechanism handles quorum independently without requiring the epsilon tiebreaker.
The first node to join the cluster does not hold epsilon in a 2-node cluster HA configuration because epsilon is explicitly removed from both nodes in this topology.
Node uptime duration has no bearing on epsilon assignment; epsilon follows quorum configuration rules, not runtime metrics.
The mgwd ring master role governs cluster management daemon coordination and is unrelated to epsilon assignment.
Lower system ID may influence epsilon in some multi-node cluster scenarios, but in a 2-node cluster HA configuration epsilon is held by neither node.
When cluster HA is enabled in a 2-node cluster, ONTAP removes epsilon from both nodes because the cluster HA interconnect provides its own quorum determination mechanism. The epsilon voting weight is unnecessary in this topology since the two nodes communicate directly over the HA interconnect to resolve split-brain scenarios without a tiebreaker vote.
Concept tested: Epsilon assignment in 2-node cluster HA
Source: https://docs.netapp.com/us-en/ontap/system-admin/manage-cluster-quorum-voting-concept.html
Topics
Community Discussion
No community discussion yet for this question.