NS0-157 · Question #147
NS0-157 Question #147: Real Exam Question with Answer & Explanation
The correct answer is D: set both nodes that are coming down to "ineligible". In a 4-node ONTAP cluster, quorum requires a majority of votes to keep the cluster operational. Each node holds one vote, and Epsilon provides the tiebreaker vote. When taking down 2 of 4 nodes, only 2 votes remain - exactly half, which is not a majority. Without Epsilon on a sur
Question
Options
- Areassign the master of all RDB rings to a node that will be staying up
- Bmigrate node-management LIFs to a node that will be staying up
- Cmove Vserver root volumes to a node that will be staying up
- Dset both nodes that are coming down to "ineligible"
- Eensure that Epsilon is assigned to one of the nodes that will be staying up
Explanation
In a 4-node ONTAP cluster, quorum requires a majority of votes to keep the cluster operational. Each node holds one vote, and Epsilon provides the tiebreaker vote. When taking down 2 of 4 nodes, only 2 votes remain - exactly half, which is not a majority. Without Epsilon on a surviving node, the cluster cannot maintain quorum and will halt. Therefore: (E) Epsilon must be moved to a surviving node to provide the tiebreaker and keep the cluster online. (D) Setting the nodes being shut down to 'ineligible' removes them from quorum calculations cleanly, preventing unexpected quorum loss. Migrating LIFs (B) and moving Vserver root volumes (C) are good practices but are not the critical quorum-protection steps. Reassigning RDB ring masters (A) is not a required pre-shutdown step.
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