N10-009 · Question #53
A network administrator needs to divide 192.168.1.0/24 into two equal halves. Which of the following subnet masks should the administrator use?
The correct answer is D. 255.255.255.128. Understanding Subnetting: Original Network: 192.168.1.0/24 has a subnet mask of 255.255.255.0, which allows for 256 IP addresses (including network and broadcast addresses). Objective: Divide this network into two equal subnets. Calculating Subnet Mask: New Subnet Mask: To…
Question
A network administrator needs to divide 192.168.1.0/24 into two equal halves. Which of the following subnet masks should the administrator use?
Options
- A255.255.0.0
- B255.255.254.0
- C255.255.255.0
- D255.255.255.128
How the community answered
(25 responses)- A16% (4)
- B4% (1)
- C4% (1)
- D76% (19)
Explanation
Understanding Subnetting: Original Network: 192.168.1.0/24 has a subnet mask of 255.255.255.0, which allows for 256 IP addresses (including network and broadcast addresses). Objective: Divide this network into two equal subnets. Calculating Subnet Mask: New Subnet Mask: To divide 192.168.1.0/24 into two equal halves, we need to borrow one bit from the host portion of the address, changing the subnet mask to 255.255.255.128 (/25). Subnet Breakdown: First Subnet: 192.168.1.0/25 (192.168.1.0 - 192.168.1.127) Second Subnet: 192.168.1.128/25 (192.168.1.128 - 192.168.1.255) Each subnet now has 128 IP addresses (126 usable IP addresses, excluding the network and broadcast addresses).
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