N10-005 · Question #722
Which of the following are valid hosts for the Private IP Address range 172.16.0.x /23? (Select TWO).
The correct answer is A. 172.16.0.255 C. 172.16.1.1. A /23 network starting at 172.16.0.0 spans 172.16.0.0 to 172.16.1.255, making any address in that range except the network address (172.16.0.0) and broadcast address (172.16.1.255) a valid host.
Question
Which of the following are valid hosts for the Private IP Address range 172.16.0.x /23? (Select TWO).
Options
- A172.16.0.255
- B172.16.0.0
- C172.16.1.1
- D172.16.8.0
- E172.16.256.255
How the community answered
(36 responses)- A81% (29)
- B11% (4)
- D6% (2)
- E3% (1)
Why each option
A /23 network starting at 172.16.0.0 spans 172.16.0.0 to 172.16.1.255, making any address in that range except the network address (172.16.0.0) and broadcast address (172.16.1.255) a valid host.
172.16.0.255 falls within the 172.16.0.0/23 block (172.16.0.0 - 172.16.1.255) and is not the network address or the broadcast address (172.16.1.255), making it a valid assignable host.
172.16.0.0 is the network address of the 172.16.0.0/23 subnet and cannot be assigned to a host.
172.16.1.1 also falls within the 172.16.0.0/23 block and is neither the network address nor the broadcast address, so it is a valid host.
172.16.8.0 is outside the 172.16.0.0/23 range, which ends at 172.16.1.255, so it does not belong to this subnet.
172.16.256.255 is an invalid IP address because the value 256 exceeds the maximum octet value of 255 and cannot exist in any subnet.
Concept tested: Subnetting and valid host identification for /23 network
Source: https://learn.microsoft.com/en-us/troubleshoot/windows-client/networking/tcpip-addressing-and-subnetting
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