Which of the following IP address/CIDR combinations represent public address space? (Select TWO).

The correct answer is B. 172.15.1.1/16 E. 193.168.2.1/24. RFC 1918 defines three private (non-routable) IPv4 ranges: 10.0.0.0/8, 172.16.0.0/12 (covering 172.16.0.0–172.31.255.255), and 192.168.0.0/16. Any address outside these ranges is public. A (10.1.1.1) is private (10.0.0.0/8). C (172.16.1.1) and D (172.31.1.1) are both private…

Networking concepts

Question

Options

A10.1.1.1/8
B172.15.1.1/16
C172.16.1.1/16
D172.31.1.1/16
E193.168.2.1/24
F224.0.0.1/32

How the community answered

(43 responses)

A
5% (2)
B
86% (37)
C
2% (1)
F
7% (3)

Explanation

RFC 1918 defines three private (non-routable) IPv4 ranges: 10.0.0.0/8, 172.16.0.0/12 (covering 172.16.0.0–172.31.255.255), and 192.168.0.0/16. Any address outside these ranges is public. A (10.1.1.1) is private (10.0.0.0/8). C (172.16.1.1) and D (172.31.1.1) are both private (within 172.16.0.0/12). B (172.15.1.1) is public because 172.15.x.x falls below the private range start of 172.16.0.0. E (193.168.2.1) is public because it starts with 193, not 192 - it is not in the 192.168.0.0/16 private range. F (224.0.0.1) is a multicast address, not public unicast space.

Topics

#public IP addresses#private IP ranges#RFC 1918#CIDR notation

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