LX0-101 · Question #346
The output for the command ifconfigeth0 is shown below: Eth0 Link encap:Ethernet HWaddr 00:0C:29:CB:FA:30 inetaddr:192.168.246.11 Bcast:192.168.246.255 Mask:255.255.255.0 UP BROADCAST RUNNING…
The correct answer is D. IP=$(LANG= ifconfigethO | grep inet | awk'{ print$2}' | cut-d: ^f2). See the full explanation below for the reasoning.
Question
The output for the command ifconfigeth0 is shown below:
Eth0 Link encap:Ethernet HWaddr 00:0C:29:CB:FA:30 inetaddr:192.168.246.11 Bcast:192.168.246.255 Mask:255.255.255.0 UP BROADCAST RUNNING MULTICAST MTU:1500 Metrlel RX packets:4721 errorsrO dropped:0 overruns:0 frame:0 TX packets:3216errors:0dropped:0overruns:0 carrier:0 collisions^) txqueuelen:1000 RX bytes:445184 (434.7 Kb) TX bytes:512968 (500.9 Kb) lnterrupt:185 Base address:0xl080 Which of the following commands should be used in a bash script that needs a variable containing the IP address of the eth0 interface?
Options
- AIP=LANG= ifconfig ethO | awk'{print $2 )' | cut -f2
- BIP='LANG= ifconfig ethO | grep inet | cut-d: -f2 | awk {print $1 Y
- CIP='LANG= ifconfig ethO | awk'{print $3 }"
- DIP=$(LANG= ifconfigethO | grep inet | awk'{ print$2}' | cut-d: ^f2)
- EIP=$(LANG=ifconfigethO| grep inet | cut-d:-f2)
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- E2% (1)
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