JN0-633 · Question #170
Click the Exhibit button. [edit] useu@host# run show log debug Feb3 22:04:32 22:04:31.983991:CID-0:RT:ge-0/0/1.0:5.0.0.25/59028- >25.0.0.25/23, tcp, flag 18 Feb3 22:04:32 22:04:31.983997:CID-0:RT…
The correct answer is C. The packet is part of the first-packet path processing. D. TCP sequence checking is enabled. See the full explanation below for the reasoning.
Question
Click the Exhibit button. [edit] useu@host# run show log debug Feb3 22:04:32 22:04:31.983991:CID-0:RT:ge-0/0/1.0:5.0.0.25/59028- >25.0.0.25/23, tcp, flag 18 Feb3 22:04:32 22:04:31.983997:CID-0:RT: find flow: table 0x582738c0, hash 53561(0xffff), sa 5.0.0.25, da 5.0.0.25, sp 59028, dp 23, proto 6, tok 20489 Feb3 22:04:32 22:04:31.984004:CID-0:RT:Found: session id 0x14f98. sess tok 20489 Feb3 22:04:32 22:04:31.984005:CID-0:RT: flow got session. Feb3 22:04:32 22:04:31.984006:CID-0:RT: flow session id 85912 Feb3 22:04:32 22:04:31.984009:CID-0:RT: vector bits 0x2 vector 0x53a949e8 Feb3 22:04:32 22:04:31.984012:CID-0:RT: tcp sec check. Feb3 22:04:32 22:04:31.984015:CID-0:RT:mbuf 0x4a82cd80, exit nh 0xa0010 Which two statements are true regarding the output shown in the exhibit? (Choose two.)
Options
- AThe outgoing interface is ge-0/0/1.0.
- BThe packet is subject to fast-path packet processing.
- CThe packet is part of the first-packet path processing.
- DTCP sequence checking is enabled.
How the community answered
(43 responses)- A7% (3)
- B12% (5)
- C81% (35)
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