Juniper
JN0-104 · Question #264
Given the host IP address of 192.168.100.60 and a network mask of 255.255.255.224 (or /27), which address represents the correct network address for the referenced host?
The correct answer is D. 192.168.100.32. Network is a class C network: 192.168.100.32/27 Binary: 11000000.10101000.01100100.001 00000
Networking Fundamentals
Question
Given the host IP address of 192.168.100.60 and a network mask of 255.255.255.224 (or /27), which address represents the correct network address for the referenced host?
Options
- A192.168.100.48
- B192.168.100.16
- C192.168.100.0
- D192.168.100.32
How the community answered
(21 responses)- A14% (3)
- B5% (1)
- C5% (1)
- D76% (16)
Explanation
Network is a class C network: 192.168.100.32/27 Binary: 11000000.10101000.01100100.001 00000
Topics
#subnetting#/27 mask#network address calculation#IPv4 addressing
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