nerdexam
Juniper

JN0-102 · Question #376

What is the network ID address of the IPv4 subnet that includes the IP address 114.180.192.120/28?

The correct answer is C. 114.180.192.112/28. To determine the network ID for 114.180.192.120/28, you must identify the subnet mask and calculate the network address by performing a bitwise AND operation with the given IP.

Routing Fundamentals

Question

What is the network ID address of the IPv4 subnet that includes the IP address 114.180.192.120/28?

Options

  • A114.180.192.118/28
  • B114.180.192.100/28
  • C114.180.192.112/28
  • D114.180.192.106/28

How the community answered

(23 responses)
  • A
    4% (1)
  • B
    9% (2)
  • C
    70% (16)
  • D
    17% (4)

Why each option

To determine the network ID for 114.180.192.120/28, you must identify the subnet mask and calculate the network address by performing a bitwise AND operation with the given IP.

A114.180.192.118/28

114.180.192.118/28 is a host address within the 112-127 subnet, not the network ID.

B114.180.192.100/28

114.180.192.100/28 falls into a different subnet (the 96-111 range) based on the /28 mask.

C114.180.192.112/28Correct

A /28 subnet mask means 28 network bits, or 255.255.255.240. For the last octet, converting 120 to binary (01111000) and 240 to binary (11110000) and performing a bitwise AND yields 01110000, which is 112 in decimal. Thus, the network ID is 114.180.192.112/28.

D114.180.192.106/28

114.180.192.106/28 also falls into a different subnet (the 96-111 range) based on the /28 mask.

Concept tested: IPv4 subnetting calculation

Source: https://www.cisco.com/c/en/us/support/docs/ip/ip-version-4-ipv4/13795-27.html

Topics

#subnetting#IPv4 addressing#network ID

Community Discussion

No community discussion yet for this question.

Full JN0-102 Practice