Juniper
JN0-102 · Question #325
Given the host IP address of 192.168.100.60 and a network mask of 255.255.255.224 (or /27), which address represents the correct network address for the referenced host?
The correct answer is D. 192.168.100.32. Network is a class C network: 192.168.100.32/27 Binary: 11000000.10101000.01100100.001 00000
Routing Fundamentals
Question
Given the host IP address of 192.168.100.60 and a network mask of 255.255.255.224 (or /27), which address represents the correct network address for the referenced host?
Options
- A192.168.100.48
- B192.168.100.16
- C192.168.100.0
- D192.168.100.32
How the community answered
(44 responses)- A5% (2)
- B16% (7)
- C7% (3)
- D73% (32)
Explanation
Network is a class C network: 192.168.100.32/27 Binary: 11000000.10101000.01100100.001 00000
Topics
#subnetting#network address#IP addressing#CIDR
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